![]() If you have a small load using the current lower of 30mA. You need to use 5A transformer, Diodes rectifier is Bridge 10A 100V.Īnd Capacitor filter is 2,200uF x 5 (in parallel) = 10,000 uF 35V (total). If you want more current up to 5A, 8A, 10A. You may use the voltage of the transformer up is 20V. Or the other hand, if you cannot find more capacitors. You may connect them in parallel to more capacitance. You don’t like to calculate a lot, right? Use 2,000uF per 1A load current right now. Capacitor Filter(C1)-It keeps output voltage is stable when using a load. Or you can get 1N4007 in parallel both can get 2A.ģ. ![]() In this I use 1N5402, they can give 3A output. Diodes rectifier(D1-D4)-use 2 times of load current. So, we should 18V 2A secondary transformer.Ģ. If no load the voltage is about 26V.Īnd In load voltage may be lower 22V. Then, How much voltages of the transformer(ACV)?Īs Principle of unregulated power supply DCV is 1.414 times of ACV. Or 1.5A in this case.īut we cannot find a 1.5A transformer. We should it is at least 1.5 times of load current. In the circuit, we have to choose 4 components lists.
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